8x^2+4x-22=0

Solution for 8x^2+4x-22=0 equation:

8x^2+4x-22=0

a = 8; b = 4; c = -22;
Δ = b2-4ac
Δ = 42-4·8·(-22)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-12\sqrt{5}}{2*8}=\frac{-4-12\sqrt{5}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+12\sqrt{5}}{2*8}=\frac{-4+12\sqrt{5}}{16}
$